How to Write the Net Ionic Equation for Ba(NO3)2 + Na2CO3 = BaCO3 + NaNO3

How to Write the Net Ionic Equation for Ba(NO3)2 + Na2CO3 = BaCO3 + NaNO3

There are three main steps for writing the net ionic equation for Ba(NO3)2 + Na2CO3 = BaCO3 + NaNO3 (Barium nitrate + Sodium carbonate). First, we balance the molecular equation.

Second, we write the states and break the soluble ionic compounds into their ions (these are the strong electrolytes with an (aq) after them). Finally, we cross out any spectator ions. These are the ions that appear on both sides of the ionic equation.

If you are unsure if a precipitate will be present when writing net ionic equations, you should consult a solubility table for the compound. Another option to determine if a precipitate forms is to have memorized the solubility rules. In this reaction, BaCO3 will be insoluble and will be a precipitate (solid) and fall to the bottom of the test tube. We therefore write the state symbol (s) after the compound that precipitates out of solution.

If you are unsure if a compound is soluble when writing net ionic equations you should consult a solubility table for the compound.

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Important Skills

Finding Ionic Charge for Elements: https://youtu.be/M22YQ1hHhEY
Memorizing Polyatomic Ions: https://youtu.be/vepxhM_bZqk
Determining Solubility: https://www.youtube.com/watch?v=5vZE9K9VaJI

More Practice

Introduction to Net Ionic Equations: https://youtu.be/PXRH_IrN11Y
Net Ionic Equations Practice: https://youtu.be/hDsaJ2xI59w
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General Steps:

1. Write the balanced molecular equation.
2. Write the state (s, l, g, aq) for each substance.
3. Split soluble compounds into ions (the complete ionic equation).
4. Cross out the spectator ions on both sides of complete ionic equation.
5. Write the remaining substances as the net ionic equation.

  How to Balance Ba3N2 + H2O = Ba(OH)2 + NH3

Writing and balancing net ionic equations is an important skill in chemistry and is essential for understanding solubility, electrochemistry, and focusing on the substances and ions involved in the chemical reaction and ignoring those that don’t (the spectator ions).

More chemistry help at http://www.Breslyn.org


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